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Add Boggle board and cell abstractions
WIP: Building subtrees of boggle board based on dictionary
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+132
-18
@@ -1,10 +1,63 @@
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'''Dictionary Utils'''
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'''Boggler Utils'''
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from __future__ import annotations
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class BoardCell:
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'''Boggle Board cell'''
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def __init__(self, row: int, col: int, letter: str, adjacent_indexes: list[list[str]]) -> BoardCell:
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self.row = row
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self.col = col
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self.letter = letter
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self.adjacent_indexes = adjacent_indexes
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def __str__(self):
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return f"({self.row}, {self.col}: {self.letter}. Adjacent nodes: {self.adjacent_indexes})"
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class BoggleBoard:
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'''Boggle board structure'''
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def __init__(self, board: list[list[str]], max_word_len: int = 14) -> BoggleBoard:
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self.height: int = len(board)
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self.width: int = len(board[0]) if self.height > 0 else 0
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self.max_word_len = min(max_word_len, self.width * self.height) # max word length is determined by size of the board
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self.board = {}
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for row in range(0, self.height):
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for col in range(0, self.width):
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#self.adjacency_dict[(row, col)] = self.__get_adjacent_indexes(row, col)
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adjacent_indexes = self.__get_adjacent_indexes(row, col)
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self.board[(row, col)] = BoardCell(row, col, board[row][col], adjacent_indexes)
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def __get_adjacent_indexes(self, row, col):
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'''Return adjecency list for board of size `row x col`'''
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indexes = []
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if row > 0:
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indexes.append((row-1, col)) # up
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if col > 0:
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indexes.append((row-1, col-1)) # up-left
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if col < self.width:
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indexes.append((row-1, col+1)) # up-right
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if row < self.height:
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indexes.append((row+1, col)) # down
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if col > 0:
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indexes.append((row+1, col-1)) # down-left
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if col < self.width:
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indexes.append((row+1, col+1)) # down-right
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if col > 0:
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indexes.append((row, col-1)) # left
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if col < self.width:
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indexes.append((row, col+1)) # right
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return indexes
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def get_letter_at(self, row: int, col: int) -> str:
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'''Return the value at the specified row x column'''
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return self.board[row][col]
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class WordNode:
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'''A node that indicates a single letter in a word. Used to populate a WordTree'''
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def __init__(self, char: str, is_word: bool, children: dict['WordNode'] = None) -> 'WordNode':
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def __init__(self, char: str, is_word: bool, parent: WordNode = None, children: dict[WordNode] = None) -> WordNode:
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self.char = char
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self.is_word = is_word
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self.children = children if children is not None else {}
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self.parent = parent
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def add_child_node(self, node):
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'''Add child node to `children` dictionary, indexed by the nodes' `char`'''
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@@ -17,38 +70,51 @@ class WordNode:
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return self.__str__()
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class WordTree:
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'''A tree populated by WordNode(s) to complete words from a given wordlist'''
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def __init__(self, wordlist: list[str], alphabet: str, max_word_len: int = 16) -> WordNode:
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self.wordlist = wordlist
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'''A tree populated by WordNode(s) to complete words from a given root letter and wordlist'''
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def __init__(self, alphabet: str, root: str, words: list[str] = None, max_word_len = 16) -> WordTree:
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self.alphabet = alphabet
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self.wordlist = words
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self.root = root
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self.active_node: WordNode = None
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self.max_word_len = max_word_len
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# Generate root nodes for each letter of the alphabet
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self.tree = {}
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for char in alphabet:
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self.tree[char] = WordNode(char, False)
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# Generate root node
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self.tree[root] = WordNode(root, False)
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# Populate tree from wordlist
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for word in wordlist:
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for word in words:
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self.__insert_word(word)
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def __str__(self):
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return ", ".join(self.wordlist)
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def __insert_word(self, word):
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def __insert_letter(self, letter: str, parent: WordNode):
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'''Create WordNode for `letter` and into WordTree under `parent`'''
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parent.children[letter] = WordNode(letter, False, parent)
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def __insert_word(self, word: str) -> bool:
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'''Returns True if word was inserted into the tree, otherwise False'''
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if word is None or word[0] != self.root:
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return False
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curr_node = self.tree[word[0]]
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# print(word[0])
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for letter in word[1:self.max_word_len]:
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# Insert new WordNode for each letter that doesen't already exist in the tree
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if letter not in curr_node.children:
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curr_node.children[letter] = WordNode(letter, False)
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self.__insert_letter(letter, curr_node)
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# print(letter)
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curr_node = curr_node.children[letter]
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# Mark the last node of the word
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curr_node.is_word = len(word) <= self.max_word_len
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print(f"Added: {word[:self.max_word_len]}")
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return True
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def search(self, word) -> bool:
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def search(self, word: str) -> bool:
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'''Return True if a given word is in the tree otherwise return False'''
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if len(word) == 0 or word is None:
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return False
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curr_node = self.tree[word[0]]
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for char in word[1:]:
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if char not in curr_node.children:
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@@ -58,17 +124,65 @@ class WordTree:
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return curr_node.is_word
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def generate_board_sub_tree(self, boggle_board: BoggleBoard, start_cell: BoardCell) -> WordTree:
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'''Return subtree of board given a particular root (first letter)'''
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if start_cell.letter != self.root:
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print("ERROR: the start_cell and WordTree root must match!")
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return None
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sub_tree = WordTree(self.alphabet, self.root)
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root = self.root
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used_nodes = {}
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sub_tree.active_node = start_cell
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dict_ptr = self.tree[root]
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# Build WordTree to max depth
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for _ in range(0, min(boggle_board.max_word_len, self.max_word_len)):
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adjacent_letters = [boggle_board.board[pos] for pos in sub_tree.active_node.adjacent_indexes]
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for pos in sub_tree.active_node.adjacent_indexes:
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letter = boggle_board.board[pos]
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if pos not in used_nodes and letter in dict_ptr.children:
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sub_tree.active_node.children[letter] = dict_ptr.children[letter]
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# TODO: find way to track used_nodes to avoid loops
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# either check the word path by recursing up via the parents
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# or pass it along, probably rework WordNode or BoardCell or make
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# an intermediate object
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# used_nodes
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return sub_tree
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if __name__ == "__main__":
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tree = WordTree(['anger',
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sample_dict = [
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'aero',
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'anger',
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'ant',
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'ape',
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'argue',
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'ash',
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'assuage',
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'aunt',
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'auspice',
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'bigger',
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'bit',
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'bite',
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'biter',
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'cart',
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'cast',
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], "abcdefghijklmnopqrstuvwxyz")
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print(tree)
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print(tree.search('cast'))
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print(tree.search('hype'))
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]
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tree = WordTree("abcdefghijklmnopqrstuvwxyz", "a", sample_dict)
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print(tree.search('anger'))
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print(tree.search('argues'))
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board = [
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"aucd",
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"eegh",
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"hios",
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"trea"
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]
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boggle_board = BoggleBoard(board)
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sub_tree = tree.generate_board_sub_tree(boggle_board, boggle_board.board[(3, 3)])
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print(sub_tree.search("anger"))
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